35=g^2-2g

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Solution for 35=g^2-2g equation:



35=g^2-2g
We move all terms to the left:
35-(g^2-2g)=0
We get rid of parentheses
-g^2+2g+35=0
We add all the numbers together, and all the variables
-1g^2+2g+35=0
a = -1; b = 2; c = +35;
Δ = b2-4ac
Δ = 22-4·(-1)·35
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-12}{2*-1}=\frac{-14}{-2} =+7 $
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+12}{2*-1}=\frac{10}{-2} =-5 $

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